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Topic: **Topics to write about in college newspaper****Question:**
So I'm a freshman and for of my classes I picked creative writing but it turned out to be journalism, so this teacher is making us write for the school newspaper (Also, it is to late for me to switch out now) Anyways, we were supposed to pick a topic to do but the topic i was doing some girl stole.
The teacher stuck me with a stupid one about a class that has all seniors and some girls that don't like. I tried talking to one of them over facebook but it didn't work so i have Absolutely no way to do this. I seriously can't afford to get bad grades in school because I want to get into a good college.
What should I do?
i need to interview people for it..

July 22, 2019 / By Jenelle

try and be optimistic things could be a lot worse. And you might get some good ideas on this website http://www.twilightzoneradio.com/listen.html

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There are 4 line segments AB, BC, CD, DA (a) This is needed for part (c) The midpoint of AB is (4,1) The midpoint of BC is (1,-3.5) The midpoint of CD is (-3,0) The midpoint of DA is (0,4.5) (c) The gradient of the lines can be found by looking at the change in y over the change in x Let the midpoint of AB be written as M(AB) etc The change in y for M(AB) and M(BC) is 1 - -3.5 = 4.5 The change in x for M(AB) and M(BC) is 4 - 1 = 3 So the gradient is 4.5/3 which is 1.5 The change in y for M(BC) and M(CD) is -3.5 - 0 = -3.5 The change in x for M(BC) and M(CD) is 1 - -3 = 4 So the gradient is -3.5/4 which is -0.875 The change in y for M(CD) and M(DA) is 0 - 4.5 = -4.5 The change in x for M(CD) and M(DA) is -3 - 0 = -3 So the gradient is -4.5/-3 which is 1.5 The change in y for M(DA) and M(AB) is 1 - 4.5 = -3.5 The change in x for M(DA) and M(AB) is 4 - 0 = 4 So the gradient is -3.5/4 which is -0.875 Since there are two pairs of parallel sides (same gradient) then we have a parallelogram. The lengths of the sides can be found with Pythagoras's theorem. The length of the line from M(AB) to M(BC) Using the calculations above: √(4.5² + 3²) = 5.41 The length of the line from M(BC) to M(CD) √((-3.5)² + 4²) = 5.32 The length of the line from M(CD) to M(DA) √((-4.5)² + (-3)²) = 5.41 The length of the line from M(DA) to M(AB) √((-3.5)² + 4²) = 5.32 I hope this helps

hello! uhmm..i can only offer you a very little simple help, just letter a, because i know letter b is manageable and i haven' deal with gradient yet.. to find the midpoint of each side first you must be able to know the midpoint formula: the midpoint of a segment whose endpoints have coordinates (x1,y1( and (x2, y2) is the point with coordinates: (x1+x2/2 and y1+y2/2) http://regentsprep.org/Regents/math/midpoint/Lmidpoint.htm -try that link, you might misunderstood the formula that i've written for you so try to openthat for a clear view of the formula the sides of your quadrilateral are AB, BC, CD and AD..right?? all of these are considered as line segment with a midpoint.. compute for the midpoint of each first side: line segment AB A (2,4) B (6,-2) 2+6/2 , 4+-2/2 midpoint of line segment AB: (6,1) ___ second side: line segment BC B(6, -2) C(-4, 5) midpoint of line segment BC (1, 3/2) do the same with line segment CD and AD hope that helps

It looks like you have to use the answer from part b to get part c. If you try to solve for part c for the original equation, you won't get the answers you provided. The formula for slope is (Y1 - Y2)/(X1 - X2) So for example, to find the slope for line CD, C is (-4, -5) D is (-2, 5) Slope is (-5 - 5)/(-4 - (-2)) = -10/(-4 + 2) = -10/-2 = 5 (This is why I said you probably have to use part b to get part c) The formula for side lengths is sqrt([X1 - X2]^2 + [Y1-Y2]^2) So for line CD: sqrt([-4 - (-2)]^2 + [-5 - 5]^2) = sqrt([-2]^2 + [-10]^2) = sqrt(104) = about 10.2 Again, this is different than any of the answers you provided. On your test/exam, I would ask your teacher if you are ever unsure in a situation like this. It seems kind of mean not to specify which part to solve for.

Use the distance formula (for length) USE THIS SITE...it's easy to understand and helpful http://www.purplemath.com/modules/distform.htm <---Will change your life!!! Once the find the length of each side ur good! For gradient (which is slope...) use the slope formula...if u don't know it go to purplemath again (the website) Since I'm guessing ur in geometry,this site may help u http://www.geocities.com/mathfair2002/school/geo/geo1.htm Hope I helped EDIT: My answer is right...but the other answers look kinda complicated.

You may just have to accept that mistakes sometimes have consequences that can't be repaired. If you've lost him, you've lost him. Grieve and move on. But I wouldn't blame you for making one more attempt before you did so, and it has to be a good one. Here's what I'd do: I'd give him space for about two weeks, give him a chance to cool down his anger a bit and not feel stifled. Then I'd send him a nice "I'm sorry" Hallmark card accompanied by a short letter in which I apologized at least 4 times for lying, explained what I was afraid of that made me lie to him, acknowledges that I know he might not be able to forgive me and that's his right, but that if he could find it in his heart to give me a second chance, I would make sure that he wouldn't regret it. Then accept his answer, whatever it is. (And if you don't hear from him at all, you know the answer is "No." Don't think he didn't get the letter or didn't read it enough or anything like that. One shot, then back off forever unless he approaches you. And it's going to hurt like hell for months and you're going to be miserable for months, so break out the chocolate, the country music and the movies about love lost and get a lot of tissues. But you WILL make it out the other end eventually.)

IF a guy is going to be THIS bitter to you instead of being forgiving, then maybe you are better off without him. You can't go on and on and on chasing somebody who refuses to give you a second chance. All that i can say is if you haven't tried talking to him yet, try. If that fails, just move on and know to be honest next time.

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