1012 Shares

# I'm so screwed for my class tomorrow?

Topic: Topics to write about in college newspaper
July 22, 2019 / By Jenelle
Question: So I'm a freshman and for of my classes I picked creative writing but it turned out to be journalism, so this teacher is making us write for the school newspaper (Also, it is to late for me to switch out now) Anyways, we were supposed to pick a topic to do but the topic i was doing some girl stole. The teacher stuck me with a stupid one about a class that has all seniors and some girls that don't like. I tried talking to one of them over facebook but it didn't work so i have Absolutely no way to do this. I seriously can't afford to get bad grades in school because I want to get into a good college. What should I do? i need to interview people for it..

## Best Answers: I'm so screwed for my class tomorrow?

Fenella | 6 days ago
try and be optimistic things could be a lot worse. And you might get some good ideas on this website http://www.twilightzoneradio.com/listen.html
👍 160 | 👎 6
Did you like the answer? I'm so screwed for my class tomorrow? Share with your friends

We found more questions related to the topic: Topics to write about in college newspaper

There are 4 line segments AB, BC, CD, DA (a) This is needed for part (c) The midpoint of AB is (4,1) The midpoint of BC is (1,-3.5) The midpoint of CD is (-3,0) The midpoint of DA is (0,4.5) (c) The gradient of the lines can be found by looking at the change in y over the change in x Let the midpoint of AB be written as M(AB) etc The change in y for M(AB) and M(BC) is 1 - -3.5 = 4.5 The change in x for M(AB) and M(BC) is 4 - 1 = 3 So the gradient is 4.5/3 which is 1.5 The change in y for M(BC) and M(CD) is -3.5 - 0 = -3.5 The change in x for M(BC) and M(CD) is 1 - -3 = 4 So the gradient is -3.5/4 which is -0.875 The change in y for M(CD) and M(DA) is 0 - 4.5 = -4.5 The change in x for M(CD) and M(DA) is -3 - 0 = -3 So the gradient is -4.5/-3 which is 1.5 The change in y for M(DA) and M(AB) is 1 - 4.5 = -3.5 The change in x for M(DA) and M(AB) is 4 - 0 = 4 So the gradient is -3.5/4 which is -0.875 Since there are two pairs of parallel sides (same gradient) then we have a parallelogram. The lengths of the sides can be found with Pythagoras's theorem. The length of the line from M(AB) to M(BC) Using the calculations above: √(4.5² + 3²) = 5.41 The length of the line from M(BC) to M(CD) √((-3.5)² + 4²) = 5.32 The length of the line from M(CD) to M(DA) √((-4.5)² + (-3)²) = 5.41 The length of the line from M(DA) to M(AB) √((-3.5)² + 4²) = 5.32 I hope this helps