4382 Shares

# Water of the oceans and water vapor in the atmosphere transfer great quantities of heat from the tropics to t?

Topic: Heat transfer homework
July 19, 2019 / By Jaydon
Question: 11 Please only respond if you are positive of your answers please, i cannot afford to get any questions wrong thanks! Water of the oceans and water vapor in the atmosphere transfer great quantities of heat from the tropics to the poles. Atmospheric circulation accounts for _____ of the transfer, while ocean circulation accounts for _______. Choose one answer. a. (1/3, 2/3) b. (2/3, 1/3) c. (1/4, 3/4) d. (3/4, 1/4)

## Best Answers: Water of the oceans and water vapor in the atmosphere transfer great quantities of heat from the tropics to t?

Evelyn | 8 days ago
If you can't afford to get any questions wrong, then you have to do your own homework - how do you know that any of the answers you get here are right? b.
👍 104 | 👎 8
Did you like the answer? Water of the oceans and water vapor in the atmosphere transfer great quantities of heat from the tropics to t? Share with your friends

We found more questions related to the topic: Heat transfer homework

Originally Answered: If JimZ is a scientist, why can't he accept that water vapor makes up about 0.4 percent of the atmosphere?
What's being referred to is an experimental average, so, it does no good to deny it or cite opinion. After enough research, it should be accepted. From credible sources, I have noticed 4000 ppm or 25mm many times in the past. If it was sucked out of the air with a straw and put in a glass, they would not accept it. You're doing the right thing by focusing on this again and again. Here is another way to interpret the inverse molar ratio: 2.5 grams of water at 1 mol per 18 grams is: A = 2.5 g / (18 g/mol) = (2.5/18) mol (particles) 1kg = 1000 grams of air at 1 mol per 29 grams is: B = 1000 g / (29 g/mol) = (1000/29) mol (particles) P = A/B * 100 ≈ 0.4% And, part of the Hartmann reference can be interpreted this way since we don't need to integrate: Δp =ρ*g*Δz = 1000 kg/m^3 * 9.8*N/kg * 0.025 m = 1000 * 9.8 * 0.025 = 245 N/m^2 = 245 pascal ΔPair ≈ 100000 pascal P = Δp / ΔPair * (29/18) * 100 ≈ 0.4 % which is the same as your answer to your other question.
Originally Answered: If JimZ is a scientist, why can't he accept that water vapor makes up about 0.4 percent of the atmosphere?
Well, based soley on my rewatching of ET, Alien, Mac and Me, Predator, Arrival, Independence Day, and Mars Attacks, my conclusion is that the percentage of water vapor is probably very different on his home planet ...

Colena
Effectively, the earth is a divergent sink of IR flux resulting in a mean positive temperature gradient. This is due to in phase feedback between the flux and increasing CO2 and H20 particle density to name just two. Although out of phase feedbacks are present, they are not on average greater than positive feedbacks. Edit: The data, if true, indicates that there are slowly increasing levels of CO2 and H2O over a time scale measured in decades. In the gas phase (and liquid) this means more kinetic and quantum potential excited states of energy on the surface and in the atmosphere. Again, assuming the data I've studied is correct, a simple application of quantum theory, kinetic theory, and deductive reasoning proves the case to me beyond a reasonable doubt. Nature has way of cycling up and down. Currently, she is on the upswing. To answer your question directly without proof if I understand your terminology and meaning correctly: Water vapor has a average positive feedback that is stronger now than in the past.
👍 30 | 👎 -1

Benedicta