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Topic: **Pre calculus homework****Question:**
A. Goes through the points (4,8) and (8,17)
B. Is parallel to the result in part (a) but goes through the point (-12,20)
Please help, I started school today and she gave us homework for precalculus right away, but didn't review so I forgot what algebra 2 was like over summer

July 19, 2019 / By Gyneth

A. Use the two-point form of the equation of a line: y - y1 = ((y2-y1)/(x2-x1)) * (x - x1). Here, y1 = 8; y2 = 17; x1 = 4; x2 = 8. Substitute these: y - 8 = ((17-8)/(8-4)) * (x - 4), or y - 8 = (9/4)(x - 4), or y - 8 = (9/4)x - 9, or y = (9/4)x - 1. The slope m is seen to be 9/4. B. Parallel lines have equal slopes, so the second line has slope 9/4 also. Now use the point-slope form of the equation of a line: y - y1 = m(x - x1). Here, y1 = 20; m = 9/4; x1 = -12. Substitute: y - 20 = (9/4)(x - (-12)), or y - 20 = (9/4)(x + 12), or y - 20 = (9/4)x + 27, or y = (9/4)x + 47.

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Equation of the Line - y = mx + b m = Slope = Rise/ run B = Y intercept Point- Slope Equation of a line : y - y1 = m(x - x1)

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The line y = 7x - 10 has a slope of 7 and an intercept of -10. A parallel line will have a slope of 7 and a different intercept. So the equation is y = 7x + b In order to find out what b is, replace x and y by the coordinates of a point on the line. In your case, x = -3 and y = 3. Plug those in, solve for b.

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