Quadratic Equation Help? 10 points for best answer?
Topic: Rewrite my paper free
May 24, 2019 / By Francisca Question:
I have to rewrite quadratic equations in expanded form into factored form. The thing is, I have a few problems that have a (-1x^2) instead of (1x^2). I'm a bit confused...
Can anyone help and provide an explanation?
Best Answers: Quadratic Equation Help? 10 points for best answer?
Darcey | 7 days ago
Since you have an equation you multiply EVERY term by -1
(If the =0 were not there then first factor out -1)
multiply by -1 and get
x^2 + 10x + 24 = 0
(x + 6)(x + 4) = 0
x + 6 =0.......x + 4 = 0
x = -6....x = -4
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👍 202 | 👎 7
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We found more questions related to the topic: Rewrite my paper free
Originally Answered: How do you solve a quadratic equation with just three points?
Equation of a quadratic equation is:
y = ax^2 +bx +c
you have 3 points
substitute the 3 points into the equation
y1 = ax1^2 +bx1 +c
y2 = ax2^2 +bx2 +c
y3 = ax3^2 +bx3 +c
you have 3 equations with 3 unknowns to solve for a, b and c
Well, first, to get rid of your problem you can multiply the whole equation by -1 to get x^2+10x+24=0. Then, to factor, you think about what two multiples of the third term add up to the coefficient (the number before the variable) of the second term. This always works when the coefficient of the first number is 1, but if it isn't, it will not. 6 times 4 = 24 and 6+4=10. Therefore, the factored form of this equation is (x+6)(x+4)=0 or (x+4)(x+6)=0, either way is the same.
👍 80 | 👎 -2
First the quadratic formulation for a given equation ax^2+bx+c=0 is right here: -b±sqrt(b^2+(-4*a*c)) / 2a as a effect enable: a=4 b=6 c-4 utilising your calculator, you will desire to get the two values for x (the effect from the quadratic equation above) to be 0.5 and -2 There you flow!
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