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# TEN POINTS.high school geometry help (DESPERATE)? Topic: Homework area rules
July 16, 2019 / By Dandrenor ## Best Answers: TEN POINTS.high school geometry help (DESPERATE)? Bonduca | 2 days ago
First lets get nomenclature right The triangle vertices are A,B and C. A, B C are also the (interior) angles at the respective vertices. a is the line opposite A a is also the length of the line opposite a. Similarly with b and c h is the altitude from A to a and is perpendicular to a j is the altitude from B to b and k is he altitude from C to c j, k and h are also the lengths of the altitudes. First we must prove the sin rule. h = c * sin B also h= b * sin C Therefore c*sin B= b* sin C Therefore c/sinC=b/sinB Area1 = a *h Area1 = a * b* sinC k=a * sin B Area2= k * c Area 2 = c*a*sinB = a*c*sin B But we know that c*sinB = b*sinC Therefore Area 2 = a * b* sinC Which is the same as Area1 Proof completed.
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We found more questions related to the topic: Homework area rules Originally Answered: How Bad is it to Fail Geometry in High School?
Good luck you need math in almost everything and I don't think you ll pass if you don't get a passing grade i suggest you get your books open and don't study everything just the basics of the chapters but its really important Wishing you luck.:) Originally Answered: How Bad is it to Fail Geometry in High School?
Failing geometry is not the end of the world. Throwing away the opportunities you are being offered with both hands, is. If you go to somewhere like India of Africa where so many children compete for any school space you will realise how reckless (or ridiculous) you are being. If your school has a counsellor go and see them and sort out how you are going to get yourself back on track. Alanna
I'll borrow a diagram from: http://polymathematics.typepad.com/photo... The proof doesn't require that you know what an orthocenter is, or prove that it exists. I just don't feel like creating my own diagram, and this one was the closest to your setup that I could find. Let e = CK and f = CH. Then we have e/b = f/a. (They are both equal to cos C, if you know trigonometry. If not, use the fact that triangles ACK and BCH are similar: they both contain angle C and a right angle.) Rearranging, we find that ae = bf, so a^2 e^2 = b^2 f^2. Now use the Pythagorean Theorem: a^2 = f^2 + k^2, so (f^2 + k^2) e^2 = b^2 f^2. Do a little algebra: b^2 f^2 - e^2 f^2 - e^2 k^2 = 0 b^2 f^2 - e^2 f^2 - e^2 k^2 + b^2 k^2 = b^2 k^2 (k^2 + f^2)(b^2 - e^2) = b^2 k^2 a^2 * (b^2 - e^2) = b^2 k^2 Use the Pythagorean Theorem again: b^2 - e^2 = h^2, so a^2 h^2 = b^2 k^2. Taking square roots, we conclude that ah = bk. The hint says that you will need two diagrams. This is stupid. Since we didn't make any particular assumptions about b and k, the proof to show that ah=cl is exactly the same. No mathematician would ever write a separate proof that ah=cl. I would say something like, "By an identical argument, ah=cl." Though if your teacher is really that harsh, you might not want to point out how dumb her hint is, so maybe you should write a second proof.
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Assume the next 2 axioms: A1: a million+X = a million. A2: two*X = X. Given A1 and A2, reply the next: a million.) a million+6 = ? two.) two*eight = ? Just considering I recognise the axioms to be unsuitable does now not imply that I can not preserve them as actual lengthy sufficient to accurately finish the solutions are, below the ones axioms: a million.) a million two.) eight
👍 69 | 👎 -16 Originally Answered: Geometry Questions. in desperate need of help?
The answer to 1 is B. 2 c 3b If you want homework help, i have an online homwork help service that i offer. http://myonlinetutor.wordpress.com/ Its an easy way to get your homework done when you dont understand it.

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