5322 Shares

Alot of maths problems?

Alot of maths problems? Topic: Ask questions about math homework
July 21, 2019 / By Dalinda
Question: i need to know alot about 40, is it; 1. odd or even 2.composite or prime 3.factors and multiples (up to at least 10) i know this is alot so if you like maths, then please do it :) thankyou so much omg u dont know how much i will love the person who answers this! <3 :) xoxoxoxoxoox 4.other numeral systems 5.square or triangular number (or neither) 6.fibonacci or pascals triangle or any other intresting facts i need these answers for these numbers; 40 11 2000 27 4 6 7 8 163 102 11 yeah bout that.... yes this is homework but give me a break will ya? and yea i know its even, but its just to show u the questions.
Best Answer

Best Answers: Alot of maths problems?

Blessing Blessing | 4 days ago
Yeah, someone didn't do their homework, did they? Are you seriously asking if 40 is an odd number or even? What grade are you in?
👍 156 | 👎 4
Did you like the answer? Alot of maths problems? Share with your friends

We found more questions related to the topic: Ask questions about math homework


Blessing Originally Answered: Maths problems help please?
1) 1600 = 16 * 100 = 2^4 * 10 * 10 = 2^6 * 5^2 2) 30m:40m 3) (4x + 16)/4 = 4(x + 4)/4 = x + 4 4) x/5 - 1 < 4 x/5 < 5 x < 25 5) For this one, you basically want the amount of internal cubes to be larger than the amount of external cubes. Internal cubes = (x - 2)³ External cubes = x³ - (x - 2)³ You want (x - 2)³ > x³ - (x - 2)³ If we work out the point at which point they equal, then the answer we want will be the integer above. (x - 2)³ = x³ - (x - 2)³ x³ - 6x² + 12x - 8 = x³ - (x³ - 6x² + 12x - 8) x³ - 6x² + 12x - 8 = 6x² - 12x + 8 x³ - 12x² + 24x - 16 = 0 If you solve this, you will get a number of x = 9.69.... So the smallest block in which the internal cubes outnumber the external cubes is 10*10*10
Blessing Originally Answered: Maths problems help please?
Hi, 1) Write 1600 as a product of prime numbers in index form. 1600 = 2^6*5^2 2) Divide 70m into the ratio 3:4 ¾ ÷ 70m = ¾ × 1/(70m) = 3/(280m) 3) Factorize and Simplify: 4x + 16 / 4 4x + 16 ---------- = ...4 4(x+4) --------- = x + 4 <== answer ..4 4) Solve the inequality x/5 - 1<4 - Is the answer x<15? No x/5 - 1 < 4 Add 1. x/5 < 5 Multiply by 5. 5(x/5) < 5(5) x < 25 <== answer 5) This is a bit of a tricky one.... - If twenty-seven cubes are glued together to form a 3*3*3 block, one cube will be completely hidden. In a 4*4*4 block, eight of the sixty-four cubes are completely hidden. What are the dimensions of the smallest block in which more than half the cubes are hidden? 10*10*10 is the smallest block in which more than half the cubes are hidden. In it you can see 4 sides for walls of 10x 9 blocks( only 9 so you don't repeat the corner column on both sides) plus 8 x 8 on the top center and 8 x 8 on the bottom center for a total of 488 on the outside. 8*8*8 or 512 are on the inside, which is more than half. A quick way to do this on a graphing calculator is to enter y = (x - 2)^3/x^3 and look at the table to see the first value greater than .5 for y. I hope that helps!! :-)
Blessing Originally Answered: Maths problems help please?
(1). 1600 800*2 8*100*2 8*4*25*2 (2^3)*(2^2)*(5^5)*(2^1) = 1600 (All powers and bases are prime numbers). (2). 3:4, add the numbers and you get 7 parts. 70/7 = 10 10*3 = 30 10*4 = 40 → 30m : 40m (3). 4x + 16/4 4x + 4 4(x + 1). (4). x/5 - 1 < 4 (x5) x - 5 < 20 x < 20 + 5 x < 25 (5). 10*10*10. That is 1000 cubes and 512 will be covered.

Airlea Airlea
40 If the number is having 0, 2, 4, 6, or 8 in its unit place then it is even number so 40 is even. 11 If the number is having 1, 3, 5, 7, or 9 in its unit place then it is odd number all prime numbers except 2 are odd but prime numbers are divisible by 1 and the number it self. 11 is divisible by 1 and 11 only so it is prime. 2000 -------------- even 27 ----------- odd but divisible by 3 so it is not prime. 4 ---------- even 6 ---------- even 7 odd but divisible by 1 and 7 itself so it is prime. 8 ---------- even 163 it is odd and prime. 102 even 11 ---------- as above. -----
👍 60 | 👎 -5

Airlea Originally Answered: Solving these Maths Problems?
1. Kate has two pieces of material. One piece is 72cm wide and the other piece is 90cm wide. She wants to cut both pieces into strips of equal width that are as wide as possible. How wide does she cut the strips? Solution: HCF of 72,90 is 18 Cm.........Ans 2. Tom exercises every 14 days and Katie every 9 days. Tom and Katie both exercised on March 12/ On what date will they both exercise together again? Sol LCM of 14 and 9 is 126 days .....................Ans 3. Ms. Hoover has 160 crayons and 30 colouring books to give to her students. If each student gets an equal number of crayons and an equal number of colouring books what is the largest number of students she can have in her class? Solution HCF of 160 and 30 is 10 students ................Ans 4. Bart is making a board game with dimensions of 16cm by 25cm. He wants to use square tiles. What are the dimensions of the largest tile he can use? Sol HCF of 16 and 25 is 1x1 tile ....................Ans 5. Beginning on Monday of each week and running until Friday, The Breakfast Show gives away $100 to every 100th caller who gets through to the show. During the week before a Saturday night concert, the show offers two free tickets to the concert for every 70th caller. How man callers must get through before one wins the tickets and the $100? Sol HCF of 100 and 70 = 10 ...................Ans
Airlea Originally Answered: Solving these Maths Problems?
1) I guess 3cm is a smart with if you want no waste of material.You also ca use width 6cm and 9cm. Other solutions I do not find. 2) Guess they will meet at 14 x 9 days, that means 126 days. 3) My answer is 10 students. 4)He cannot use squares bigger than 1 squared Centimetres 5) Guess there must come in 700 calls to a winner of both a concert thicket and 100 dollars.

If you have your own answer to the question ask questions about math homework, then you can write your own version, using the form below for an extended answer.