HELP! ME! 7th Grade Math?
Topic: How to write a cubed number
July 16, 2019 / By Cuthbert Question:
1) A 2-centimeter cube was enlarged using a scale factor of 7/1. Find the length of the model and the number of 1-centimeter cubes used to build it.
2) Write about it - If you are finding a percent of a number and the percent is between 0% and 100%, then in what range is the answer?
3) Jane estimates that she ran about 2867 miles last year. She ran 3 times a week. Estimate how many miles she ran each day.
4) Write about it -- How can you use common fractions to estimate what percent one number is of another number? Explain.
Best Answers: HELP! ME! 7th Grade Math?
Athelstan | 9 days ago
1.) 2 X7/1 / 1?14
2.) all really #'s less than 100 and greater than zero
3.)3 X 52 then divide that number by 2867
4.) so much of a fraction of a percent
👍 126 | 👎 9
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Originally Answered: 59% Grade 12 English, and Grade 10 Science 70%, and Grade 10 Math 70% Can I get into any program?
"i do nottttttttttttt want to to do highschool math as a 19 year old"
My answer might suck but here it is anyway...
What's worse, doing math as a 19yr old, or stuck in some job you don't like when you are 29 because you didn't want to do math at 19.
I hear where you are coming from, I had to take Math9 three freekin' times before I finally passed... math is the devil's work. So is black licorice and socks. Ew.
Regardless what I'd do is take tutoring or whatever it takes to get better at math - if you want the gold ring at the end. It'll suck and you'll hate every minute of it but the reward will be not having a lifetime of asking 'dya want any fries with that'.
If you don't want to be say an IT Tech because it nvolves math, set your sights on the more artistic endeavors - web page design. That doesn't take math necessarily - but does take lots of computer html coding knowledge. That you could get at say a community college instead of a university.
"someone kill me"
... but then all I'd get at Christmas is a lump of coal. [or worse, math homework].
EDIT TO ADDRESS:
"will i get into this program?"
According to the website...
"Although not required for admission, credits in Grade 12 Mathematics, keyboarding skills, and any art and/or computer graphics credits are suggested."
... so it would seem even doing relatively okay at math would be perfectly fine, not like you have to be in the top 10% or anything.
I'd say yes, you'd get in based on what their website says.
It's not obvious to compare 3/8 and 2/3, but look at it this way: would you rather slice a pie into 3 pieces and take two (2/3 of a pie), or slice it into 8 pieces and take 3 (3/8 of a pie)? If you like pie, you will probably make the first choice, and that's because 2/3 is greater than 3/8. Thus 3/8 < 2/3. The math way to do it is to multiply the left sides by 3/3 and the right side by 8/8 (both are fancy ways of writing 1). Then you have 9/24 on the left side and 16/24 on the right side. Now the number on the bottom is the same and it's much easier to compare; clearly 9/24 < 16/24. In other words, you're slicing the pie into 24 pieces; 3/8 of the pie is the same as taking 9 pieces, and 2/3 of the pie is the same as taking 16 pieces.
👍 40 | 👎 4
you use a proportion. you put ur number over 100 and then is over of... is is the same as an equal sign, of is a multiplication sign. when they say 25 is 50% of what number? you find the is and of and switch them 25=.50xW w is your variable. that could also be
---- = ---- < This is a proportion. you need to plug in the numbers.
100 X On the right is where you put your "is over of"
👍 32 | 👎 -1
if you dont know how to do your homework, there is a big chance you wont do so hot.
Ask your teacher for help, it will make math a lot easier when you get to high school if you understand the basics from 7th/8th grade.
trust me im in 10th grade and i never even pay attention to the teacher because its basically just a review of 7th grade
👍 24 | 👎 -6
Originally Answered: Really need help with math HW, 10 POINTS! (6th grade math, 3 questions, should not be hard)?
For problem 1. Right the problem like this... 3/4 / 3 which is... 3/4 * 1/3 so you get 3/12 which reduces to 1/4 so she eats 2 pieces meaning she ate 2/4 or 1/2 of the whole.
(3/4 * 1/3) * 2 =1/2
2. (3/4) * 21 = 63/4 = 15 3/4 pounds of fudge (i hope it's peanut butter)
3. 1 3/4 = 7/4
2 1/2 = 5/2
Find least common denominator which is 4 so 5/2=10/4
now just multiply 7/4 * 10/4 you get 70/16
she will need 4 3/8 cups of brown sugar