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Topic: **Spring essays****Question:**
Now, it is 12/2011. As I mention something I did during 02/2011 - 04/2011, how should I include the time?
Like: I worked in D.R. this spring , or I worked in D.R. last spring ?
I feel confused because my ESL teacher marked the latter as wrong in my essay.

July 17, 2019 / By Princess

As a former ESL teacher, I'm confused, too. It might help if you included the sentence preceding and following this one. EDIT: I asked my husband about your question. We both agree that "last spring" makes more sense. Did your teacher give you any explanation for marking your sentence wrong?

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Did you like the answer? We found more questions related to the topic: **Spring essays**

Hello Ducky This is one of those "Initial potential energy = final kinetic energy" questions. But it has a little trick, the one friction patch strips away part of the final kinetic energy by the work of friction. PEinitial = Wfriction + KEfinal Now, solve each piece PEinitial = 1/2 * k * x^2 Wfriction = u * N * R (I'm gonna call the length of the friction patch R = 0.05 m) Wfriction = u * (m * g) * R KEfinal = (1/2) * m * v^2 PEinitial = Wfriction + KEfinal (1/2) * k * x^2 = u * (m * g) * R + (1/2) * m * v^2 Let's get rid of the1/2 on each side k * x^2 = 2 * u * (m * g) * R + m * v^2 Solve for x x^2 = (2 * u * (m * g) * R + m * v^2) / k x = SQRT((2 * u * (m * g) * R + m * v^2) / k) x = SQRT((2 * (0.45) * ((1.1 kg) * (9.81 m/s^2) * (0.05 m) + (1.1 kg) * (2.1 m/s)^2) / (750 N/m) x = 0.084 m x = 8.4 cm Good Luck

I don't undesrtand ur question really and what are u telling me to find: 1.) Spring constant/energy stored in spring/gravity/density/ WHAT hEY TELL IT CLEARLY!

U[0] = (1/2)kx[0]^2 U[1] = (1/2)k(2x[0])^2 = 4.(1/2)kx[0]^2 = 4U[0] U[2] = (1/2)k(x[0]/2)^2 = (1/4).(1/2)kx[0]^2= U[0]/4 2U[0] = 2(1/2)kx[0]^2 = (1/2)k{sqrt(2)x[0]}^2 Compression sqrt(2)x[0] The last one is similar.

the tension of rope : T = m2 . g = 5 . 10 = 50 N The equilbrium on the mass a million : T = m1.g + Fs ( Fs = The spring tension) 50 = 20 + Fs ----> Fs = 30 N The Hooke's regulation : Fs = ok . x -----> x = 30/3 hundred = 0.a million m the skill skill stored indoors the spring : PE = (a million/2) F . x = (a million/2). 30 . 0.a million = a million.5 J

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