4059 Shares

Topic: **How to write a graph equation in standard form****Question:**
Write the standard form of the equation of the line that passes through B(-2, 3) and is perpendicular to the graph of 2y + 6 = 0
I don't get this question, any help would be great! Thanks!
I'm not being lazy, I really don't get it. I do understand, however that the slope is zero, but then wouldn't that make the equation y=3? It says that it wants it in standard form and y=3 obviously isn't in standard form.

July 18, 2019 / By Sal

A bunch of things are going on here. First off, try to visualize (or graph) the line 2y+6 = 0; this line contains all the points for which the y coordinate (height) is -3 (if 2y+6=0 then 2y = -6 and so on). Now, what kind of a line would be perpendicular to this one? Draw any perpendicular line and find two points on it; what do they have in common. Once you see that you can tell what the line through point (-2,3) must be. As far as standard form -- we have three different forms for equations of lines. Each "form" is just a rule for how to write the parts of a line. The usual way in most textbooks to show the form is Ax + By = C. (The B here is just a number, and has nothing to do with the point B). So, for the line you were given, 2y+6 = 0 the standard form would be 0x+2y=-6 -- or just 2y=-6. Many teachers would want you to eliminate the common factors among A, B and C, for for this line you'd write y = -3. This problem is made particularly easy (once you see it) because the line you started with doesn't depend on x. In most cases the equations will involve both x and y.

👍 204 | 👎 8

Did you like the answer? We found more questions related to the topic: **How to write a graph equation in standard form**

Okay! first of all, you have to find the slope of these points... Slope formula is Y2-Y1/X2-X1 Figure out which points you want to use... as Y1 Y2 X1 and X2 (1,1) (9,7) 7-1 ------ = 6/8 9-1 The formula for a liner line is y= mx+b from this point you choose between the two points given... I choose (1,1) because it's easier to calculate... m= slope y=mx+b 1=6/8 (1) +b >>> subtract 6/8 on both sides to solve for b 1/1-6/8 = 2/8=1/4 b= 1/4 plug into the equation: y= 6/8x + 1/4

First find the slope of the line. It is defined by the change in y as a function of x. so 7-1 / (9/1) = 6/8 = 3/4. Using y = mx +b. find the intercept where it works 1 = (3/4)*1 + b sovle for b and we get 1/4 = b so y(x) = (3/4)x +1/4. To check apply x = 9 and see if you get 7 9*3= 27/4 + 1/4 = 28/4 = 7.

There are two ways to write the equation of a line: y = mx+b (y-y1) = m(x-x1) The second is the best to use when you have a slope (m) and a point (x1,y1) So plugging in your values, we get (y--4) = -2/3 (x-2) y+4 = -2/3 x +4/3 y = -2/3 x +(4/3 - 12/3) y = -2/3 x - 8/3

👍 80 | 👎 7

2y + 6 = 0 y = -3 This is a horizontal line. A perpendicular to it is vertical. Since it passes through (-2, 3), the equation of the perpendicular is x = -2. http://www.flickr.com/photos/dwread/4286...

👍 73 | 👎 6

If x = 6 is the only solution, think about this: If x = h is a solution and x = k is a solution, then (x-h)(x-k) gives you the equation in standard form once you complete the expansion. In your case, the only solution is x=6 so both h and k = 6. Substitute and do the multiplication.

If you have your own answer to the question how to write a graph equation in standard form, then you can write your own version, using the form below for an extended answer.