3772 Shares

Can someone tell me the answers for these problems? I've already done them but I need to check my answers? Topic: Do homework and see answer
June 24, 2019 / By Sonny
Question: When I write sq rt it means there's a square route sign. 1. sq rt -36 / sq rt -4 2. - (16 / 2 sq rt -4) 3. - (2 sq rt -64 / sq rt -16) 4. i sq rt -16 5. -2i sq rt -16 6. sq rt -49 - i 7. sq rt -25 + i squared sq rt -36 8. -i sq rt -16 If you really don't know how to do these or you aren't sure then please don't confuse me more by guessing and sending me wrong answers. Thanks a million, even if you only do some of the problems.  Oscar | 3 days ago
just so we know you've actually done your homework, why don't you let us see what your answers are and then we can let you know whether or not they are correct!!
👍 94 | 👎 3
Did you like the answer? Can someone tell me the answers for these problems? I've already done them but I need to check my answers? Share with your friends

We found more questions related to the topic: Do homework and see answer Originally Answered: Need to check my answers for dividing radicals problems.?
For all of these, note that square root is the same as raising to the 1/2 power, so for 1. (8sqrtx^5)/3sqrt(x)= (8(x^5)^.5)(3(x)^.5)= And when you have a fraction containing only terms of the same power, you can move the power outside the fraction. Note that this is confusing to look at in computer typing, so maybe try writing it out on paper to make it clearer? (8/5)((x^5)/x)^.5= Divide the x, (8/5)(x^4)^.5= When powers are multiplied as above, you can multiply across the parenthesis, (8/5)(x^2)= 1.6x^2 The rest are done the same way, except number 3 For 3, anytime a number under a radical can be divided by a term twice then, you can move the term outside. 18 can be divided by 3 twice. 18/3=6 6/3=2 Thus, the 3 can be moved outside. 4sqrt(18)= 3*4sqrt(2)= 12sqrt(2) Hope this helps. Happy Easter! Originally Answered: Need to check my answers for dividing radicals problems.?
?(27c) may be simplified to 3?(3c) ?(32c^3) may be simplified to 4c?(2c) so now you have (3?(3c))/(4c?(2c)) in case you may not have an intensive in the denominator (relies upon on the instructor) then multiply the coolest and backside via?(2c) that delivers you (3?(6c^2))/(8c^2) simplifies to (3c?6)/(8c^2) (you do no longer might desire to worry approximately plus or minus c even nonetheless you're looking the sq. root of c squared given which you already comprehend that c can not be destructive (?(27c) tells you that)) and that simplifies on your very final answer of (3?60)/(8c) Leo
1. sq rt -36 / sq rt -4 = 3 2. - (16 / 2 sq rt -4) = -4/i 3. - (2 sq rt -64 / sq rt -16) = -4 4. i sq rt -16 = -4 5. -2i sq rt -16 = 8 6. sq rt -49 - i = 6i 8. -i sq rt -16 = 4 I'm not sure what 7 means
👍 30 | 👎 2 Originally Answered: Can someone check my answers to problems relating to permutations and combinations?
1. order is not important, so it's just 7! 2. You're right. 3. Not sure, I think more info is needed. 5. _ _ _ _ _ _ _ 7 slots, the first one cannot be 0 or 1. No such thing as 7C8, that wouldn't even make sense because how can you choose 8 objects from 7 available? ten digits available, they can repeat. (8)(10)^6 It means there are only 8 possibilities for the first digit, and 10 for each of the remaining 6. 6. You're right. 7. I think you're right. 8. Map out possibilities. 5 heads, 6 heads, 7 heads, 8 heads. You can use the combination formula here to help. It's similar to solving probabilities that ask if you flip coin 5 times, what's the probability it comes up with at least 2 heads? Hope this helps. Originally Answered: Can someone check my answers to problems relating to permutations and combinations?
Did you attempt to regulate your password. If not perchance you should make a sparkling account. in case you attempt to bypass surfing each day then dont get on for some days and then go surfing again to be certain if that works.

If you have your own answer to the question do homework and see answer, then you can write your own version, using the form below for an extended answer.